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Math Help - polar conversion

  1. #1
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    polar conversion

    I can't figure how to convert this polar equation to a cartesian equation.
     r = 2 - \sin2\theta
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by cubs3205 View Post
    I can't figure how to convert this polar equation to a cartesian equation.
     r = 2 - \sin2\theta
    r = 2 - \sin 2 \theta .............................simplify the double angle sine

    \Rightarrow r = 2 - 2 \sin \theta \cos \theta .................multiply through by r^2

    \Rightarrow r^3 = 2r^2 - 2r \sin \theta \cdot r \cos \theta ........now convert

    \Rightarrow \left( x^2 + y^2 \right)^{3/2} = 2x^2 + 2y^2 - 2xy

    and you can attempt to simplify that monstrosity if you so desire, i would leave it like that though
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