Yep you're correct if you integrate that you'll get F(x)=(1/3)x^3-2x^2+c and when you integrate that from 0 to 4 you get 10.67. Might be a typo.
Hi can you please explain this to me,
, why must k be from 0 to 4 such that the area is 13units^2?
I integrated x(x-4) from 0 to 4, I only got the area as 10.something...it's not 13?
If that is so, then what should the value for k be such that
Made this one up myself, I just wanted to know how to get k=4 in the previous question..
Please help, thank you so much!