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Math Help - integration

  1. January 13th 2013, 06:15 AM #1
    Kvandesterren
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    integration

    ∫ 2sin(2x+y) dx
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  2. January 13th 2013, 06:28 AM #2
    sbhatnagar
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    Re: integration

    \int 2\sin(2x+y)dx

    substitute u=2x+y

    \int 2\sin(2x+y)dx = \int \sin u du = -\cos u+C

    =-\cos(2x+y)+C
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  3. January 13th 2013, 09:45 PM #3
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    Re: integration

    Quote Originally Posted by Kvandesterren View Post
    ∫ 2sin(2x+y) dx
    sbhatnagar's answer is correct if y is considered to be independent of x (so you are really doing partial integration, which is the opposite of partial differentiation). However it's incorrect if y is a function of x...
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