# Math Help - integration

1. ## integration

∫ 2sin(2x+y) dx

2. ## Re: integration

$\int 2\sin(2x+y)dx$

substitute $u=2x+y$

$\int 2\sin(2x+y)dx = \int \sin u du = -\cos u+C$

$=-\cos(2x+y)+C$

3. ## Re: integration

Originally Posted by Kvandesterren
∫ 2sin(2x+y) dx
sbhatnagar's answer is correct if y is considered to be independent of x (so you are really doing partial integration, which is the opposite of partial differentiation). However it's incorrect if y is a function of x...