Results 1 to 2 of 2

Math Help - rate of change

  1. #1
    Newbie
    Joined
    Oct 2007
    Posts
    13

    rate of change

    for cos(3.14t/2) find when the particle is speeding up and slowing down, and the acceleration after 3 seconds, and the distance traveled in 4 seconds
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Forum Admin topsquark's Avatar
    Joined
    Jan 2006
    From
    Wellsville, NY
    Posts
    9,939
    Thanks
    338
    Awards
    1
    Quote Originally Posted by pageraets View Post
    for cos(3.14t/2) find when the particle is speeding up and slowing down, and the acceleration after 3 seconds, and the distance traveled in 4 seconds
    May I be the first to say

    "What????"

    I presume that your position function for the particle is
    x = cos \left ( \frac{ \pi t}{2} \right )

    So the speed function is the first time derivative and the acceleration is the second time derivative.

    Thus
    v = \frac{dx}{dt} = -\frac{\pi}{2}~sin \left ( \frac{ \pi t}{2} \right )
    and
    a = \frac{d^2x}{dt^2} = -\left ( \frac{\pi}{2} \right ) ^2 ~cos \left ( \frac{ \pi t}{2} \right )

    Can you do the rest?

    -Dan
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 3
    Last Post: April 12th 2011, 09:51 AM
  2. rate change
    Posted in the Calculus Forum
    Replies: 1
    Last Post: July 11th 2008, 03:11 AM
  3. rate of change
    Posted in the Calculus Forum
    Replies: 1
    Last Post: May 20th 2008, 07:53 AM
  4. rate of change
    Posted in the Calculus Forum
    Replies: 9
    Last Post: May 3rd 2007, 09:39 AM
  5. Rate of change
    Posted in the Statistics Forum
    Replies: 2
    Last Post: April 18th 2007, 07:27 AM

Search Tags


/mathhelpforum @mathhelpforum