Thread: Solving word problems using derivatives

Here is a plot of the revenue function for problem 1:

Yes, thank you. I managed to finish that one. I got 250 passengers. Which seems much more reasonable than my first answer of 15000...

Okay, I understand that I need to substitute x^2 in for y, but in what? In the distance formula?

How did you get 250 passengers? What is the revenue function at x = 250?

The problem said to find the number of passengers, not the greatest revenue.

Originally Posted by ktkeiper

The problem said to find the number of passengers, not the greatest revenue.

A chartering company will provide a plane for a fare of $300 per person for 100 or fewer passengers (but more than 60 passengers.) For each passenger over 100, the fare is decreased $2 per person for everyone. What number of passengers would provide the greatest revenue?

fyi, at x = 250 passengers, revenue = 0

What formula did you use? Because with my formula, the revenue came out to $62500

Originally Posted by ktkeiper

What formula did you use? Because with my formula, the revenue came out to $62500

for ...