Find the length fo the graph and compare it to the straight-line distance between the endpoints of the graph.
f(x)=ln[sex(x)] x E [0,(pi/4)]
how would you do this?
oops. haha sorry about that. about the E, im not sure what it means. thats what it has in my book. it doesnt exactly look like an E though, its more curved than straight. it just says f(x)= ln[sec(x)], x E [0, (pi/4)]
but i think you're right. though when you take the derivative of sec(x) it equals sec(x)tan(x) right? i dont quite understand how you got tanx from ln[sec(x)]
The derivative of ln(sec(x))=tan(x).
The E may be 'element of'?. Is this it, ?.
If so, they just mean that's the limits of integration.
Which we found whittles down to something easy.
Once you find your solution to the integral, compare it to: