Is it possible to integrate -(1/2)vdt, with respect to t?
I really am at a loss.. please help me! Is it differential equations? I had (dv/dt)=(-(1/2))v initially
You're not going to integrate $\displaystyle -(1/2)vdt$ wrt to $\displaystyle t.$
The equation that you have is solved by separation of variables.
Rewrite it as $\displaystyle \frac{dv}{v}=-\frac{1}{2}dt,$ and integrate the lhs wrt $\displaystyle v$, the rhs wrt $\displaystyle t.$