dR/dh = 0,
where R is 2 (hH-h2 )1/2
d [2 (hH-h2 )1/2 ] /dh = 0
2 x 1/2 (hH-h2)-1/2 x (H-2h) = 0
(H-2h)/rt (hH-h) = 0
h = H/2
this is a part of a physics question and any help is appreciated.
I get it till the 2 x1/2 part, but how did they get the (h-2h) part?
If someone could explain this to me, I'd be super-grateful!