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Math Help - Indeterminate Form Discussion - 1^(inf)

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    Indeterminate Form Discussion - 1^(inf)

    In my AP Calculus class, we had a lengthy discussion regarding the indeterminate form Indeterminate Form Discussion - 1^(inf)-codecogseqn-28.gif. Other bases to infinity either turn out to be infinity itself or 0, depending on the base. To me, that doesn't make sense. Why are quantities, such as Indeterminate Form Discussion - 1^(inf)-codecogseqn-29.gif, are determinate, but Click image for larger version. 

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ID:	26414 is not? Just want to hear some opinions.
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    Re: Indeterminate Form Discussion - 1^(inf)

    Dr. Math discusses why ...

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    Re: Indeterminate Form Discussion - 1^(inf)

    1^Infinity is and indeterminate fore because infinity is not a real number. There are no rules for how exponentiation works on something that isn't a number. Plus x=1^infinity is like you are saying infinity*ln(1) which doesn't exist.
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