Hello! How would you integrate 2^x / ln2? Thanks already!
note that:
$\displaystyle \frac{1}{\ln(2)} = \frac{\ln(2)}{(\ln(2))^2}$
you can take the denominator (which is just a constant) outside the integral, so:
$\displaystyle \int \frac{2^x}{\ln(2)}\ dx = \frac{1}{(\ln(2))^2}\int \ln(2)2^x\ dx = \frac{1}{(\ln(2))^2} \int e^{\ln(2)x} \ln(2)\ dx$
if you use the substitution $\displaystyle u = \ln(2)x$ what would $\displaystyle du$ be?