Question. Find 25^1/3 with precision of 3 decimals.

My book says:

$\displaystyle \sqrt[3]{25}=\sqrt[3]{27}\sqrt[3]{\frac{25}{27}}. $Then we can say: $\displaystyle \sqrt[3]{25}=\sqrt[3]{3(1-\frac{2}{27})}$

I didnt understand the logic. I mean, how did he go from the first affirmation to the second?

Thanks in advance,