AP Calculus Verifying a Solution to a Differential Equation Trig Function (question)

**asilvester635** · December 25th 2012, 02:08 PM

why did the -sin^2(x) change into -1 + cos^2x?

**BobP** · December 25th 2012, 02:13 PM

$\sin^{2}x+\cos^{2}x = 1.$

**asilvester635** · December 25th 2012, 02:23 PM

i don't get it

**Plato** · December 25th 2012, 02:41 PM

Originally Posted by asilvester635

i don't get it

Do you get that if $s^2+c^2=1$ then $-s^2=-1+c^2~?$

**BobP** · December 25th 2012, 02:43 PM

It's a basic trig identity that by now, (judging by what you are doing), you should be familiar with.

It can be rewritten as

$-\sin^{2}x = -1 +\cos^{2}x.$

**asilvester635** · December 25th 2012, 02:50 PM

yah i forgot its a trig identity.. thanks anyways

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