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Math Help - AP Calculus Verifying a Solution to a Differential Equation Trig Function (question)

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    AP Calculus Verifying a Solution to a Differential Equation Trig Function (question)

    why did the -sin^2(x) change into -1 + cos^2x?
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    Re: AP Calculus Verifying a Solution to a Differential Equation Trig Function (questi

    \sin^{2}x+\cos^{2}x = 1.
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    Re: AP Calculus Verifying a Solution to a Differential Equation Trig Function (questi

    i don't get it
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    Re: AP Calculus Verifying a Solution to a Differential Equation Trig Function (questi

    Quote Originally Posted by asilvester635 View Post
    i don't get it

    Do you get that if s^2+c^2=1 then -s^2=-1+c^2~?
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    Re: AP Calculus Verifying a Solution to a Differential Equation Trig Function (questi

    It's a basic trig identity that by now, (judging by what you are doing), you should be familiar with.

    It can be rewritten as

    -\sin^{2}x = -1 +\cos^{2}x.
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    Re: AP Calculus Verifying a Solution to a Differential Equation Trig Function (questi

    yah i forgot its a trig identity.. thanks anyways
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