I know how to do "normal" linear approx...but I don't know how to diff this equation. F(x)= 2^x^2 and approx f(.9) Thank you!
by the chain rule: (or you could notice that $\displaystyle 2^{x^2} = e^{x^2 \ln 2}$)
$\displaystyle \frac d{dx}2^{x^2} = 2x \ln 2 \cdot 2^{x^2} = x \ln 2 \cdot 2^{x^2 + 1}$
the tangent line approximation is given by:
$\displaystyle f(x) \approx f(a) + f'(a)(x - a)$
where $\displaystyle x = 0.9$ and $\displaystyle a = 1$
by "normal" linear approx, i guess you want the normal line. this is just the line perpendicular to the tangent line