hydrostatic pressure in a glass of water
So I have a glass of water, as shown in the picture (but I can only draw 2D in paint). Now I was wondering how I would calculate the largest occuring hydrostatic pressure (and the position) in the glass if I rotate it by an angle, small enough so the water doesn't fall out of the glass.
I know that the volume of water stays the same, so I was thinking of integrating this after maybe doing a coordinate transformation, but I'm not sure what would be the easiest way to solve this problem, as it looks fairly complicated to me.
P.S: I'm not asking for a solution (although you're free to try), just your opinion on how I would best solve this.
Re: hydrostatic pressure in a glass of water
The pressure only depends on the depth of the water( p = g h). So it is always the lowest bottom where largest pressure occurs.