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Math Help - Cone volume with triple integral

  1. #1
    Junior Member BERMES39's Avatar
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    Cone volume with triple integral

    I have tried to calculate the volume of a cone with base radius "a" and height "h" using a triple integral. Either by hand or using a CAS calculator I get the same answer: a^2*h*pi. Can someone point out where is the error?
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  2. #2
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    Re: Cone volume with triple integral

    Why not use polar cylindrical ?
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  3. #3
    MHF Contributor ebaines's Avatar
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    Re: Cone volume with triple integral

    The height from the base to the surface of the cone is not  h-\frac h a y, but rather should be  h - \frac h a \sqrt{x^2+y^2}. And I agree - using polar coordintes would make the integral much simpler to evaluae.
    Last edited by ebaines; December 18th 2012 at 12:55 PM.
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