Sorry Guys - One last Improper Integration question (e^x)/ ((e^x) -1) Why Divergent??
Sorry. I'm coming to the end of my four hour review. I try not to disturb you guys too much but I guess I'm just brain dead now.
So the problem is the integral of (e^x) / ((e^x) -1) from -1 to 1
I wasn't sure what to do at first so I made it
(e^x) -1) +1 / ((e^x) -1)
so that I could split the integral into
(e^x -1)/(e^x-1) and get x
and then
1 / ((e^x) - 1)
And then I just solved it straightup. I won't show that because it's obviously completely wrong if it's divergent.
How exactly is this done. Sorry to disturb you guys again and thank you * 1000000 + Lim x-> inifinity of x^2 (Nod)
Re: Sorry Guys - One last Improper Integration question (e^x)/ ((e^x) -1) Why Diverge
if part of the definite integral diverges, it all diverges ...

![\lim_{a \to 0^+} \left[\ln(e^x - 1) \right]_a^1](http://latex.codecogs.com/png.latex?\lim_{a \to 0^+} \left[\ln(e^x - 1) \right]_a^1)
![\lim_{a \to 0^+} \left[\ln(e - 1) - \ln(e^a - 1) \right]](http://latex.codecogs.com/png.latex?\lim_{a \to 0^+} \left[\ln(e - 1) - \ln(e^a - 1) \right])
 = \infty)