how dy/dx and y1-y2=m(x2-x1) related? I mean shouldn't dy/dx = m ?
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The tangent line to a differentiable function at the point $\displaystyle (x_1,y_1)$ is: $\displaystyle y-y_1=f'(x_1)(x-x_1)$
Originally Posted by ameerulislam how dy/dx and y1-y2=m(x2-x1) related? I mean shouldn't dy/dx = m ? dy/dx is a FUNCTION which tells you what the gradient of your function y is at any point. m is the gradient of your tangent line at a SINGLE point.
Originally Posted by Prove It dy/dx is a FUNCTION which tells you what the gradient of your function y is at any point. m is the gradient of your tangent line at a SINGLE point. If you can please provide an example that would be great! I'm like getting it and not getting it.. tx
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