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Math Help - how dy/dx and y2-y1=m(x2-x1) related?

  1. #1
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    how dy/dx and y2-y1=m(x2-x1) related?

    how dy/dx and y1-y2=m(x2-x1) related?

    I mean shouldn't dy/dx = m ?
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  2. #2
    MHF Contributor MarkFL's Avatar
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    Re: how dy/dx and y2-y1=m(x2-x1) related?

    The tangent line to a differentiable function at the point (x_1,y_1) is:

    y-y_1=f'(x_1)(x-x_1)
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  3. #3
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    Re: how dy/dx and y2-y1=m(x2-x1) related?

    Quote Originally Posted by ameerulislam View Post
    how dy/dx and y1-y2=m(x2-x1) related?

    I mean shouldn't dy/dx = m ?
    dy/dx is a FUNCTION which tells you what the gradient of your function y is at any point.

    m is the gradient of your tangent line at a SINGLE point.
    Thanks from ameerulislam
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    Re: how dy/dx and y2-y1=m(x2-x1) related?

    Quote Originally Posted by Prove It View Post
    dy/dx is a FUNCTION which tells you what the gradient of your function y is at any point.

    m is the gradient of your tangent line at a SINGLE point.
    If you can please provide an example that would be great! I'm like getting it and not getting it.. tx
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