i gave it a shot and this is what i got = (1/cosx)(1/cosx)(sinx/cosx) (I REWROTE IT) = (secx)(secxtanx) (TIME TO INTEGRATE) = (secxtanx)(secx) + C did i do it right?
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No, I think I would approach it with the substitution: and we have: Using your approach, we could let: and we have the easier to integrate: The two results are equivalent.
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