i gave it a shot and this is what i got
= (1/cosx)(1/cosx)(sinx/cosx) (I REWROTE IT)
= (secx)(secxtanx) (TIME TO INTEGRATE)
= (secxtanx)(secx) + C
did i do it right?
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No, I think I would approach it with the substitution: and we have:
Using your approach, we could let: and we have the easier to integrate:
The two results are equivalent.
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