i gave it a shot and this is what i got
= (1/cosx)(1/cosx)(sinx/cosx) (I REWROTE IT)
= (secx)(secxtanx) (TIME TO INTEGRATE)
= (secxtanx)(secx) + C
did i do it right?
Printable View
i gave it a shot and this is what i got
= (1/cosx)(1/cosx)(sinx/cosx) (I REWROTE IT)
= (secx)(secxtanx) (TIME TO INTEGRATE)
= (secxtanx)(secx) + C
did i do it right?
No, I think I would approach it with the substitution:
and we have:
Using your approach, we could let:
and we have the easier to integrate:
The two results are equivalent.