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Math Help - Calculus integration (hard)

  1. #1
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    Calculus integration (hard)

    Do I use integration by substitution?? this is a really tricky question for me
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  2. #2
    MHF Contributor MarkFL's Avatar
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    Re: Calculus integration (hard)

    Yes, try the substitution:

    u=1-x\,\therefore\,du=-dx

    Then use:

    \sec(u)\tan(u)=\frac{d}{du}(sec(u))
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    Re: Calculus integration (hard)

    LOL so the final answer is sec(1-x)... wow it's that easy...
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  4. #4
    MHF Contributor MarkFL's Avatar
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    Re: Calculus integration (hard)

    Not quite that easy...you need to correctly substitute for the differential to get:

    -\int\,d(\sec(u))=-\sec(u)+C=-\sec(1-x)+C
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