Do I use integration by substitution?? this is a really tricky question for me
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Yes, try the substitution: $\displaystyle u=1-x\,\therefore\,du=-dx$ Then use: $\displaystyle \sec(u)\tan(u)=\frac{d}{du}(sec(u))$
LOL so the final answer is sec(1-x)... wow it's that easy...
Not quite that easy...you need to correctly substitute for the differential to get: $\displaystyle -\int\,d(\sec(u))=-\sec(u)+C=-\sec(1-x)+C$
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