(cos 3x) / sin3x * (√sinē(3x) -2)

incase you aren't familiar with it, the formula for arc sec is

1/a arcsec u/a + c

a = -√2

u = sin 3x

du = 3 cos 3x

so 1/3 du = cos 3x dx

so I cancel out the top

and make since it's in the proper format I make it

I do 1/3 * a to get -√2/3 arcsec sin3x / -√2 + c

what did I do wrong, if anything?