Percentage error in Area of triangle
Hello, I'm stuck on the following question:
I only get as far as taking natural logs and then differentiation it, but have no idea on how to carry on:
ln(S) = ln(b)+ln(c)+ln(sinA)
Assuming that b and c are equal to 1, I get:
1/S dS = 1/b db + 1/c dc + cot A (sub in [A=pi/4])
That's what I gather from the text book but then I hit dead end.
Any idea on what I'm doing wrong or whether I'm completely wrong from the off?
Re: Percentage error in Area of triangle
You are given that and are both 5%. For the third term, you correctly differentiated
but you are given , so you need:
So is 5%, A is and is 1.