Thread: Find the area of the region bounded by y and the x-axis

am I on the right track here?

Yes. I would write:



edit: Don't forget the differential in your definite integral and avoid using a rounded decimal approximation (at least if you have the same professor I did).

That's fine. You can check this sort of thing here integral (-2,6) (x+3)^(1/2) dx - Wolfram|Alpha

Originally Posted by MarkFL2

Yes. I would write:

I see. So we assume u = (x+3) and go from there. Looks more professional to me. Thanks! On thing I'm not sure about though is, how did you get the 9 and 1?
EDIT: Oh nevermind. I get it now.

Originally Posted by a tutor

That's fine. You can check this sort of thing here integral (-2,6) (x+3)^(1/2) dx - Wolfram|Alpha

Oh that tool is amazing! So I take it the graph shown there is the sketch of the region.