I could use some help on the following derivative questions.....
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What help, specifically, do you need?
The rule that is being tested here is
$\displaystyle \frac{d}{dx}e^x = e^x$.
For example, the first one is just the product rule:
$\displaystyle f(x) = (x + 3)e^x$
$\displaystyle f^{\prime}(x) = 1 \cdot e^x + (x + 3)e^x = (x + 4)e^x$
-Dan
in general, $\displaystyle \frac d{dx}e^{kx} = ke^{kx}$
here, k = -1
recall that $\displaystyle \frac d{dx}cf(x) = c \frac d{dx}f(x)$ where $\displaystyle c$ is a constant.I'm also not sure what to do with 2e^x
thus, $\displaystyle \frac d{dx}2e^x = 2 \frac d{dx}e^x = 2e^x$
(basically this means, when deriving something with a constant coefficient, you can pretty much ignore the constant, find the derivative of the function, and then affix (multiply by) the constant again.
i do not know how it is in webwork, but it is probably 3^(1/3) or something like that. i don't know if cubert(3) would work either. shouldn't there be some kind of tutorial for how to enter things into your webwork program?
what?! you wrote the same thing twice, of course they are the sameand is 1/e^x not 1/e^x?
1/(e^x) = e^(-x) if that makes it any easier for you
another common way to type e to some power is to type exp(some power)
so 1/(e^x) = e^(-x) = exp(-x)