integrate from -2 to 2 sqrt(4-x^4) in terms of an area.
i dont even know what it means to integrate in terms of an area, please help!
you sure the integrand isn't $\displaystyle \color{red}\sqrt{4 - x^2}$ ? the function you posted is undefined at the limits of integration ... $\displaystyle \sqrt{4 - 2^4} = \sqrt{-12}$ ... ???
btw ... y = $\displaystyle \sqrt{4-x^2}$ is a semicircle
Last edited by skeeter; Dec 11th 2012 at 03:46 PM.