integrate in terms of area

**pnfuller** · December 11th 2012, 01:20 PM

integrate from -2 to 2 sqrt(4-x^4) in terms of an area.

i dont even know what it means to integrate in terms of an area, please help!

**Prove It** · December 11th 2012, 02:37 PM

I think it means you need to use a Riemann Sum, since at face value I can't see a way to integrate this...

**pnfuller** · December 11th 2012, 02:45 PM

how many rectangles should i do so i dont get negatives under the square root?

**skeeter** · December 11th 2012, 03:39 PM

Originally Posted by pnfuller

integrate from -2 to 2 sqrt(4-x^4) in terms of an area.

i dont even know what it means to integrate in terms of an area, please help!

you sure the integrand isn't $\color{red}\sqrt{4 - x^2}$ ? the function you posted is undefined at the limits of integration ... $\sqrt{4 - 2^4} = \sqrt{-12}$ ... ???

btw ... y = $\sqrt{4-x^2}$ is a semicircle

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