check if i did it right

so far i got

= (-2)(2^-1/2)

Now do i multiply both of them then integrate??

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- Dec 11th 2012, 09:31 AMasilvester635Indefinite Integration
check if i did it right

so far i got

= (-2)(2^-1/2)

Now do i multiply both of them then integrate?? - Dec 11th 2012, 09:48 AMMarkFLRe: Indefinite Integration
I would rewrite the integral as:

$\displaystyle \frac{1}{2}\int x^{-\frac{1}{2}}\,dx$

Next, apply the power rule for integration. - Dec 11th 2012, 10:00 AMasilvester635Re: Indefinite Integration
oh snap... yahh that's right....

is this right then

= 1/2(2x^1/2)

= x^1/2 - Dec 11th 2012, 10:46 AMskeeterRe: Indefinite Integration