$\displaystyle \int_{-\pi}^{\pi} f(x)dx $ where $\displaystyle f(x) = \left\{ {\begin{array}{rl} {6x^3,} & {\text{if }x~-\pi=<x<0} \\ {7sin(x),} & {\text{if }x~0=<x<=\pi} \\\end{array} } \right.$

I broke up the integral like this $\displaystyle \int_{-\pi}^{0} 6x^{3} dx + \int_{0}^{\pi} 7sin(x) $ . When I look at the graph of these two functions I notice that they overlap each other. Does that affect the area value in any way? I know the antiderivates will be even functions, so I think I only have to find the integral of the 1st and 4th quadrant and then just double it. If I do : $\displaystyle 2 \int_{0}^{\pi} 7sin(x) $ I get 28, but that's not correct. I'm sure I'm just not understanding something about these graphs, that's what I ask if the overlap feature means I need to break up the endpoints of the integral differently?