Consider an arbitrary point of the parabola with co÷rdinates (a,a▓+a).
Can you set up the equation of the tangent line through this point?
Then express that this line has to go through (2,-3), you'll get a quadratic equation in a.
I believe I may have found one tangent (with the negative slope, but I cant seem to find the other tangent with the positive slope)
any help appreciated
Find equations of both lines through the point (2, -3) that are tangent to the parabola y = x^2 + x
edit. working with it more heres what i got
y = -x -1
y = 5x - 4
can somebody confirm these?