Find the Maclaurin series for the function using definition of a Mclaurin series. Also, find the radius of convergence.

$\displaystyle f(x) = e^{-5x}$

- Dec 8th 2012, 03:35 AMmoonmanFind the Maclaurin series for the function using definition of a Mclaurin series
Find the Maclaurin series for the function using definition of a Mclaurin series. Also, find the radius of convergence.

$\displaystyle f(x) = e^{-5x}$ - Dec 8th 2012, 04:29 AMmoonmanRe: Find the Maclaurin series for the function using definition of a Mclaurin series
This should be the Mclaurin series? $\displaystyle \sum^\infty_{n=0} \frac{-5x^n}{n!}$

How do I find the radius of convergence? - Dec 8th 2012, 04:54 AMHallsofIvyRe: Find the Maclaurin series for the function using definition of a Mclaurin series
For power series the simplest way to find the radius of convergence is to use the "ratio test".

A series of positive numbers, $\displaystyle \sum a_n$ will converge as long as the sequence $\displaystyle \frac{a_{n+1}}{a_n}$ has a limit less than 1. (If that limit is larger than 1, it diverges. If it is equal to 1, we don't know.)

Here, $\displaystyle a_n= \frac{-5x^n}{n!}$. Those terms may not be positive but we know that a power series always converges**absolutely**inside its radius of convergence so we can take the absolute value:

$\displaystyle \left|\frac{-5x^{n+1}}{(n+1)!}\frac{n!}{-5x^n}\right|= \frac{|x|}{n+1}$

What is the limit of that as n goes to infinity? For what values of x is that limit less than 1? - Dec 9th 2012, 10:24 AMmoonmanRe: Find the Maclaurin series for the function using definition of a Mclaurin series
$\displaystyle \lim_{n \to \infty} \frac{|x|}{n+1}$

$\displaystyle \lim_{n \to \infty} \frac{\frac{|x|}{n}}{\frac{n}{n}+\frac{1}{n}}$

$\displaystyle = 0 $ Not sure I'm doing this right? - Dec 9th 2012, 10:39 AMskeeterRe: Find the Maclaurin series for the function using definition of a Mclaurin series
$\displaystyle e^{-5x} = 1 + (-5x) + \frac{(-5x)^2}{2!} + \frac{(-5x)^3}{3!} + \frac{(-5x)^4}{4!} + ... = \sum_{n=0}^\infty \frac{(-5x)^n}{n!}$

- Dec 9th 2012, 01:00 PMmoonmanRe: Find the Maclaurin series for the function using definition of a Mclaurin series
Since the ratio test = 0 then we don't know?

- Dec 9th 2012, 01:12 PMskeeterRe: Find the Maclaurin series for the function using definition of a Mclaurin series
have you used the ratio test to find a radius of convergence before?

$\displaystyle \lim_{n \to \infty} \left| \frac{(-5x)^{n+1}}{(n+1)!} \cdot \frac{n!}{(-5x)^n} \right| < 1$

$\displaystyle \lim_{n \to \infty} \left| \frac{-5x}{n+1} \right| < 1$

$\displaystyle 5|x| \cdot \lim_{n \to \infty} \frac{1}{n+1} < 1$

$\displaystyle 5|x| \cdot 0 < 1$ for all x ... so, what's the radius of convergence? - Dec 9th 2012, 07:12 PMmoonmanRe: Find the Maclaurin series for the function using definition of a Mclaurin series
infinity! Thank you sir!