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- Dec 7th 2012, 06:45 AMmagicodx/dt problem
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Attachment 26124 - Dec 7th 2012, 07:13 AMHallsofIvyRe: dx/dt problem
$\displaystyle \frac{x}{4}= tan(\theta)$

- Dec 7th 2012, 07:23 AMmagicoRe: dx/dt problem
- Dec 7th 2012, 08:16 AMHallsofIvyRe: dx/dt problem
"Rate of theta" doesn't make any sense, nor does "theta= rad/sec". You mean you want the

**rate of change**of theta, with respect to time. So differentiate the equation I gave you with respect to t.