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Math Help - another area under the curve qn

  1. #1
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    another area under the curve qn

    Hi I dont know where I went.wrong again! Really would appreciate the help! For y=rand, over the interval x=0 to pi/4, I am supposed to find the area between the x-axis,x=pi/4. I got my area to be -ln|sqrt(2)/(2)|by integrating tanx from 0 to pi/4, but it is wrong!
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  2. #2
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    Re: another area under the curve qn

    Sorry for the typo! It is y=tanx, that's the graph given. Thank you!
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  3. #3
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    Re: another area under the curve qn

    I was wondering! Who told you it was wrong? Another of those "computer" systems where you have to give the answer in exactly the right form? I hate those things! -ln(\sqrt{2}/2) is perfectly correct but can be simplified. -ln(\sqrt{2}/2)= ln(2/\sqrt{2})= ln(\sqrt{2})= ln(2)/2. Try one of those forms.
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