Thread: limit of a function

Hey, could someone explain how to solve this limit?



thanks

Is that to the power of 3x or multiplied by 3x??

If it's multiplied by 3x than it's simple it'll be the lim as x tends to infinity of (x^2/x^2) * lim as x tends to infinity of 3x which will give you 1*infinity which is infinity. If it's raised to the power of 3x then you will transform it to e^(lim x->infinity 3xlog((x^2+x-1)/(x^2-x+1))). Now see what you can solve from that.