integral of (1/sqrt x) = integral (x ^(-1/2)} = x^(-1/2 + 1)/(-1/2 + 1) = sqrt(x)/(1/2)
If you integrate the square root of 2/x does it come out to just 2x because when i rewrite it its going to be the square root of 2x^-1
Then i turn the square root into an exponent which looks like this 2x^-1+2.... -1 + 2 = 1.... So i have just 1 as an exponent.... now i just have 2x
Your problem seems to me like you need to do the indefinite integral. You should be able to put the limits in yourself. As for the other question:
You might need a review of multiplication of radicals, which is a pre-Calculus topic.
-Dan
@Plato: Sorry for the snipe. I thought you were gone.