integral of (1/sqrt x) = integral (x ^(-1/2)} = x^(-1/2 + 1)/(-1/2 + 1) = sqrt(x)/(1/2)
If you integrate the square root of 2/x does it come out to just 2x because when i rewrite it its going to be the square root of 2x^-1
Then i turn the square root into an exponent which looks like this 2x^-1+2.... -1 + 2 = 1.... So i have just 1 as an exponent.... now i just have 2x
You might need a review of multiplication of radicals, which is a pre-Calculus topic.
@Plato: Sorry for the snipe. I thought you were gone.