I am given that a solid is bounded by: y= x^2-1, y+z=0, z=0.
I am asked to find the bounds of a triple integral with respect to dz, dy, dx. So, I basically traced each graph with respect to the xy, xz, and yz plane. The bounds that I got are: (x=-1 to x=1), (y=x^2-1 to y=0) and (z=0 to z=-y). Can anyone tell me if I am approaching this problem correctly? I am not exactly sure if my bounds are correct.
Any help and feedback appreciated, thanks.