Math Help - differentiation

1. differentiation

3^x+log2(xy)=10

2. Originally Posted by simsima_1
3^x+log2(xy)=10
for the first term, note that $\frac d{dx}a^x = a^x \ln a$ for $a > 0$

for the second part, use the change of base formula:

$\log_ab = \frac {\ln b}{\ln a}$

3. lol...ummm i think i'm more confused now ....

4. Originally Posted by simsima_1
lol...ummm i think i'm more confused now ....
$3^x + \log_2(xy) = 10$

$\Rightarrow 3^x + \frac {\ln (xy)}{\ln 2} = 10$

now continue by implicit differentiation