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Math Help - differentiation

  1. #1
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    differentiation

    3^x+log2(xy)=10
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by simsima_1 View Post
    3^x+log2(xy)=10
    for the first term, note that \frac d{dx}a^x = a^x \ln a for a > 0

    for the second part, use the change of base formula:

    \log_ab = \frac {\ln b}{\ln a}
    Last edited by Jhevon; February 10th 2008 at 02:13 PM.
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  3. #3
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    lol...ummm i think i'm more confused now ....
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  4. #4
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by simsima_1 View Post
    lol...ummm i think i'm more confused now ....
    3^x + \log_2(xy) = 10

    \Rightarrow 3^x + \frac {\ln (xy)}{\ln 2} = 10

    now continue by implicit differentiation
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