xy(2x+3y)=2 the xy at the beginning is throwing me off i feel like i should distribute through but then again that doesnt sound right...all help much appreciated!
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Use the product rule. $\displaystyle 2x^{2}y+3xy^{2}=2$ $\displaystyle 2x^{2}\frac{dy}{dx}+4xy+6xy\frac{dy}{dx}+3y^{2}=0$ Now, solve for dy/dx
hey thanks alot...i do believe you are the same person who answered another question i had on differentiations...thanks alot!
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