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Math Help - Any chance I can hire a tutor to help me with my Calculus problems?

  1. #16
    JDS
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    Re: Any chance I can hire a tutor to help me with my Calculus problems?

    Sorry about the long delay, Things have been crazy busy for me lately.....anyhow....

    but I do not remember what I am supposed to do with an "x" as the exponent for the letter "e", furthermore, how am I supposed to substitute u and du?
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  2. #17
    MHF Contributor MarkFL's Avatar
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    Re: Any chance I can hire a tutor to help me with my Calculus problems?

    Quote Originally Posted by JDS View Post
    Next problem is:

    \int (4x - 2ex)dx

    I am still trying to work this out.... I will post back with my progress
    Write the integral as:

    4\int x\,dx-2\int e^x\,dx

    On the first term use the rule \int x^r\,dx=\frac{x^{r+1}}{r+1}+C where r\ne-1 is a constant.

    For the second term, use the rule \int e^x\,dx=e^x+C
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  3. #18
    JDS
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    Re: Any chance I can hire a tutor to help me with my Calculus problems?

    Mark, thanks so much for always being so quick to respond! I really appreciate it. Also, I know you definitely know what you are talking about here, but I just do not get it. However, here is my attempt to use the rules as you have shown them:

    4 ∫ [(x1+1)/(1+1) + C] - ex + C

    = 4 ∫ x2 - ex + 2C

    .... Am I even close?
    Last edited by JDS; December 1st 2012 at 09:52 AM. Reason: Left "4 ∫" out of my first answer
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  4. #19
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    Re: Any chance I can hire a tutor to help me with my Calculus problems?

    \int 4x - 2e^x \, dx = 2x^2 - 2e^x + C because \frac{d}{dx}(2x^2 - 2e^x + C) = 4x - 2e^x
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  5. #20
    JDS
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    Re: Any chance I can hire a tutor to help me with my Calculus problems?

    AH I think I see what I did wrong....well actually two things.

    For one I left out the "2" in the second part of the equation and then I also did not find the antiderivative of the first term with the 4. If that makes any sense.
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  6. #21
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    Re: Any chance I can hire a tutor to help me with my Calculus problems?

    point is ... you can always check your own work by taking the derivative of your solution.
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  7. #22
    JDS
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    Re: Any chance I can hire a tutor to help me with my Calculus problems?

    very true...perhaps I should take your tagline to heart! LOL!
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  8. #23
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    Re: Any chance I can hire a tutor to help me with my Calculus problems?

    If you still need a math tutor please check out Tutor Universe... and for any math educators, please join Tutor Universe to help out struggling students.
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  9. #24
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    Re: Any chance I can hire a tutor to help me with my Calculus problems?

    I am stuck on int: (10)/(5-4sinx) dx now I know that this problem uses wiarsstraus method but the thing is I get the answer in terms of tan X/2.....................(20 tan^-1((5tan(x/2) + 4)/(3)) all over 3 which is all in terms of tanx now I want to know how to put it in terms of sin and cos for restricted values of x ?
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