# Any chance I can hire a tutor to help me with my Calculus problems?

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• Dec 1st 2012, 09:04 AM
JDS
Re: Any chance I can hire a tutor to help me with my Calculus problems?
Sorry about the long delay, Things have been crazy busy for me lately.....anyhow....

but I do not remember what I am supposed to do with an "x" as the exponent for the letter "e", furthermore, how am I supposed to substitute u and du? (Headbang)
• Dec 1st 2012, 09:20 AM
MarkFL
Re: Any chance I can hire a tutor to help me with my Calculus problems?
Quote:

Originally Posted by JDS
Next problem is:

$\displaystyle \int$ (4x - 2ex)dx

I am still trying to work this out.... I will post back with my progress

Write the integral as:

$\displaystyle 4\int x\,dx-2\int e^x\,dx$

On the first term use the rule $\displaystyle \int x^r\,dx=\frac{x^{r+1}}{r+1}+C$ where $\displaystyle r\ne-1$ is a constant.

For the second term, use the rule $\displaystyle \int e^x\,dx=e^x+C$
• Dec 1st 2012, 09:49 AM
JDS
Re: Any chance I can hire a tutor to help me with my Calculus problems?
Mark, thanks so much for always being so quick to respond! I really appreciate it. Also, I know you definitely know what you are talking about here, but I just do not get it. However, here is my attempt to use the rules as you have shown them:

4 ∫ [(x1+1)/(1+1) + C] - ex + C

= 4 ∫ x2 - ex + 2C

.... Am I even close?
• Dec 1st 2012, 10:00 AM
skeeter
Re: Any chance I can hire a tutor to help me with my Calculus problems?
$\displaystyle \int 4x - 2e^x \, dx = 2x^2 - 2e^x + C$ because $\displaystyle \frac{d}{dx}(2x^2 - 2e^x + C) = 4x - 2e^x$
• Dec 1st 2012, 10:07 AM
JDS
Re: Any chance I can hire a tutor to help me with my Calculus problems?
AH I think I see what I did wrong....well actually two things.

For one I left out the "2" in the second part of the equation and then I also did not find the antiderivative of the first term with the 4. If that makes any sense.
• Dec 1st 2012, 10:09 AM
skeeter
Re: Any chance I can hire a tutor to help me with my Calculus problems?
point is ... you can always check your own work by taking the derivative of your solution.
• Dec 1st 2012, 10:13 AM
JDS
Re: Any chance I can hire a tutor to help me with my Calculus problems?
very true...perhaps I should take your tagline to heart! LOL!
• Mar 3rd 2013, 06:07 PM
ThomasHornbeck
Re: Any chance I can hire a tutor to help me with my Calculus problems?
If you still need a math tutor please check out Tutor Universe... and for any math educators, please join Tutor Universe to help out struggling students.
• Jun 4th 2013, 12:23 PM
Kizzledout2012
Re: Any chance I can hire a tutor to help me with my Calculus problems?
I am stuck on int: (10)/(5-4sinx) dx now I know that this problem uses wiarsstraus method but the thing is I get the answer in terms of tan X/2.....................(20 tan^-1((5tan(x/2) + 4)/(3)) all over 3 which is all in terms of tanx now I want to know how to put it in terms of sin and cos for restricted values of x ?
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