Re: Any chance I can hire a tutor to help me with my Calculus problems?
Sorry about the long delay, Things have been crazy busy for me lately.....anyhow....
but I do not remember what I am supposed to do with an "x" as the exponent for the letter "e", furthermore, how am I supposed to substitute u and du? (Headbang)
Re: Any chance I can hire a tutor to help me with my Calculus problems?
Quote:
Originally Posted by
JDS
Next problem is:

(4x - 2e
x)dx
I am still trying to work this out.... I will post back with my progress
Write the integral as:

On the first term use the rule
where
is a constant.
For the second term, use the rule 
Re: Any chance I can hire a tutor to help me with my Calculus problems?
Mark, thanks so much for always being so quick to respond! I really appreciate it. Also, I know you definitely know what you are talking about here, but I just do not get it. However, here is my attempt to use the rules as you have shown them:
4 ∫ [(x1+1)/(1+1) + C] - ex + C
= 4 ∫ x2 - ex + 2C
.... Am I even close?
Re: Any chance I can hire a tutor to help me with my Calculus problems?
because  = 4x - 2e^x)
Re: Any chance I can hire a tutor to help me with my Calculus problems?
AH I think I see what I did wrong....well actually two things.
For one I left out the "2" in the second part of the equation and then I also did not find the antiderivative of the first term with the 4. If that makes any sense.
Re: Any chance I can hire a tutor to help me with my Calculus problems?
point is ... you can always check your own work by taking the derivative of your solution.
Re: Any chance I can hire a tutor to help me with my Calculus problems?
very true...perhaps I should take your tagline to heart! LOL!
Re: Any chance I can hire a tutor to help me with my Calculus problems?
If you still need a math tutor please check out Tutor Universe... and for any math educators, please join Tutor Universe to help out struggling students.