Sorry about the long delay, Things have been crazy busy for me lately.....anyhow....

but I do not remember what I am supposed to do with an "x" as the exponent for the letter "e", furthermore, how am I supposed to substitute u and du? (Headbang)

- Dec 1st 2012, 09:04 AMJDSRe: Any chance I can hire a tutor to help me with my Calculus problems?
Sorry about the long delay, Things have been crazy busy for me lately.....anyhow....

but I do not remember what I am supposed to do with an "x" as the exponent for the letter "e", furthermore, how am I supposed to substitute u and du? (Headbang) - Dec 1st 2012, 09:20 AMMarkFLRe: Any chance I can hire a tutor to help me with my Calculus problems?
- Dec 1st 2012, 09:49 AMJDSRe: Any chance I can hire a tutor to help me with my Calculus problems?
Mark, thanks so much for always being so quick to respond! I really appreciate it. Also, I know you definitely know what you are talking about here, but I just do not get it. However, here is my attempt to use the rules as you have shown them:

4 ∫ [(x^{1+1})/(1+1) + C] - e^{x}+ C

= 4 ∫ x^{2}- e^{x}+ 2C

.... Am I even close? - Dec 1st 2012, 10:00 AMskeeterRe: Any chance I can hire a tutor to help me with my Calculus problems?
$\displaystyle \int 4x - 2e^x \, dx = 2x^2 - 2e^x + C$

**because**$\displaystyle \frac{d}{dx}(2x^2 - 2e^x + C) = 4x - 2e^x$ - Dec 1st 2012, 10:07 AMJDSRe: Any chance I can hire a tutor to help me with my Calculus problems?
AH I think I see what I did wrong....well actually two things.

For one I left out the "2" in the second part of the equation and then I also did not find the antiderivative of the first term with the 4. If that makes any sense. - Dec 1st 2012, 10:09 AMskeeterRe: Any chance I can hire a tutor to help me with my Calculus problems?
point is ... you can always

**check your own work**by taking the derivative of your solution. - Dec 1st 2012, 10:13 AMJDSRe: Any chance I can hire a tutor to help me with my Calculus problems?
very true...perhaps I should take your tagline to heart! LOL!

- Mar 3rd 2013, 06:07 PMThomasHornbeckRe: Any chance I can hire a tutor to help me with my Calculus problems?
If you still need a math tutor please check out Tutor Universe... and for any math educators, please join Tutor Universe to help out struggling students.

- Jun 4th 2013, 12:23 PMKizzledout2012Re: Any chance I can hire a tutor to help me with my Calculus problems?
I am stuck on int: (10)/(5-4sinx) dx now I know that this problem uses wiarsstraus method but the thing is I get the answer in terms of tan X/2.....................(20 tan^-1((5tan(x/2) + 4)/(3)) all over 3 which is all in terms of tanx now I want to know how to put it in terms of sin and cos for restricted values of x ?