implicit differentiation (I think)

Find an equation of the line tangent to the curve with equation $\displaystyle x^2 + xy + y^3 = 1$, at the

point (-1; 1)

im I right in thinking this is an implicit differentiation problem? I would implicitly find the derivative of the equation and then use point slope formula to wite the equation of the line correct?

how do I differentiate the above equation?

Re: implicit differentiation (I think)

Quote:

Originally Posted by

**kingsolomonsgrave** Find an equation of the line tangent to the curve with equation $\displaystyle x^2 + xy + y^3 = 1$, at the point (-1; 1)

Yes indeed; $\displaystyle 2x+y+xy'+3y^2y'=0$. Solve for $\displaystyle y'~.$