1. ## Laplace Transformation question

Hi, i do not know where to post this so i just figured i leave this where there are most people viewing. I need help doing question 4 only. Thanks!!

2. ## Re: Laplace Transformation question

The steady state part can be expressed in the form

$v_{steady}=A\sin (\omega t + \alpha) = A\sin \omega t \cos \alpha + A \cos \omega t \sin \alpha,$

where $A$ is the amplitude.

Equate coefficients of $\sin \omega t$ and $\cos \omega t$ with the corresponding expressions in your formula for $v_{steady},$ and eliminate the $\cos \alpha \text{ and } \ sin \alpha$ by squaring and adding.

3. ## Re: Laplace Transformation question

Originally Posted by BobP
The steady state part can be expressed in the form

$v_{steady}=A\sin (\omega t + \alpha) = A\sin \omega t \cos \alpha + A \cos \omega t \sin \alpha,$

where $A$ is the amplitude.

Equate coefficients of $\sin \omega t$ and $\cos \omega t$ with the corresponding expressions in your formula for $v_{steady},$ and eliminate the $\cos \alpha \text{ and } \ sin \alpha$ by squaring and adding.
Hi,
I'm really bad at this but if you have the time, do you mind showing how to get to the final answer?
Thanks!

4. ## Re: Laplace Transformation question

If $A\sin \theta = p \text{ and } A\cos \theta = q,$
$A^{2}(\sin ^{2}\theta + \cos ^{2}\theta) = p^{2} + q^{2},$
so
$A = \sqrt {p^{2} + q^{2}.$
And sorry, but I know absolutely nothing about the filters mentioned in the question.

5. ## Re: Laplace Transformation question

Originally Posted by BobP
If $A\sin \theta = p \text{ and } A\cos \theta = q,$
$A^{2}(\sin ^{2}\theta + \cos ^{2}\theta) = p^{2} + q^{2},$
so
$A = \sqrt {p^{2} + q^{2}.$
And sorry, but I know absolutely nothing about the filters mentioned in the question.
Sorry, but i'm a bit confused. How did you derive the Vsteady equation in post #2.
And in post #4 wouldn't A=((p^2+q^2)/(Sin^2 theta +cos^2 theta))^(1/2)

6. ## Re: Laplace Transformation question

I didn't derive anything in post 2, I simply stated what should (at your stage) be a well-known trig identity, and what allows the the expression for $v_{steady}$ given in the question to be written in an alternative form.

Another trig identity, with which you should be familiar, is used later. $\cos^{2}\theta+\sin^{2}\theta=1.$