Hi, can anyone explain how lim x->0 (x+( (e^(2x)) - (e^(3x)) / 3x+( e^(2x) )- (e^(5x))) Can be 5/21? When I try using L'Hopital I get -4/-18.
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I assume you mean: We see we have the indeterminate form 0/0, so application of L'Hôpital's rule gives: We still have the indeterminate form 0/0, so application of L'Hôpital's rule again gives:
Thanks a lot!
Last edited by Erka; November 28th 2012 at 12:35 AM.
Glad to help and welcome to the forums!
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