You could use L'Hôpital's rule to write the limit as:
I need to evaluate the lim x->0 tan^2(x)/x
I can use any method to do this. I know the limit is zero but I wasn't sure what method I could use to evaluate this.
It could be re-written as:
(sinx/cosx)(sinx/cosx)/x
The sin of 0 is 0 and therefore makes the whole function zero, would this be sufficient enough to evaluate it?