the graph of is a parabola that opens upward.
says the graph of is concave up everywhere.
Hi guys, so I'm having trouble with the following question:
For f'(x), I got 2x and for f"(x) I got 2...
I need the values for which f"(x)=0, but how can I find it then f"(x)=2? I couldn't find any similar examples on Google guys, please help.
Thanks i advance.
I tought it would never be concave down...
You can say that is concave up everywhere just because 2 > 0?
For A), the interval is (-inf,inf), but B) insists that there's still an interview where the function is concave down... I dont understand how is that possible since it is concave up everywhere...
There is no interval where is concave down. Some advice ...
(1) LOOK at the graph of . Frankly, I'm surprised that a calculus student cannot sketch this simple graph from memory.
(2) Review your notes/text over what the sign of says about the graph of .
Since the second derivative is positive for all real x, then the function is concave up for all real x. I can't help with what to enter though, since I went to school in the dark ages where a professor actually manually graded homework that was turned in by hand.