I have f(x)= and I want to find F(x)

I am also given that F(1)=0

I get F(x)=

and since F(1)=0

F(x)=

F(x)=

F(x)=

so c=17/6

however the above is wrong somewhere. I just don't see where

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- Nov 20th 2012, 07:43 AMkingsolomonsgraveanti-derivative problem
I have f(x)= and I want to find F(x)

I am also given that F(1)=0

I get F(x)=

and since F(1)=0

F(x)=

F(x)=

F(x)=

so c=17/6

however the above is wrong somewhere. I just don't see where - Nov 20th 2012, 07:54 AMskeeterRe: anti-derivative problem
looks fine to me ...

- Nov 20th 2012, 07:55 AMkingsolomonsgraveRe: anti-derivative problem
hmmm, thanks! i was entering the answer into an online test, so it could be something i entered wrong (typo) or the online system has a bug.

- Nov 20th 2012, 03:44 PMEveryStepTomRe: anti-derivative problem
Hi-

I Thought some might benefit from seeing all the steps to this problem:

Given:

f ' (x) = 8 / x^3 - 7 / x^7 Where f(1)=0

Rewrite:

f ' (x) = 8*x^(-3) - 7*x^(-7)

Integrate:

8*x^(-3+1) 7*x^(-7+1)

= ∫ -------------- - ---------------

(-3+1) (-7+1)

= 8*x^(-2)/(-2) - 7*x^(-6)/(-6)

= -4*x^(-2) + (7/6)*x^(-6) + C

Answer:

f (x) = -4 / x^2 + 7 / 6*x^6 + C

At f (1) = 0

f (1) = -4 / (1)^2 + 7 / 6*(1)^6 + C = 0

= -4 + 7/6 + C = 0

Common Denominator:

= -24 / 6 + 7 / 6 + C = 0

= -17 / 6 + C = 0

C = 17 / 6

Answer:

f (x) = -4 / x^2 + 7 / 6*x^6 + 17 / 6 - Nov 20th 2012, 03:51 PMProve ItRe: anti-derivative problem
OP - please write down here EXACTLY how you entered this into your online test. Chances are you have a syntax error somewhere.