using logarithm expression of sinh^-1

Hi all,
I'm really stuck on a question and hoping someone can point me in the right direction.

By using the logarithm expression of sinh^-1(y), show that sinh^-1(-y)=-sinh^-1y

So far im at
sinh^-1(-y)=ln((-y)+sqrt((-y)²+1))

Thanks :)
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So, you have:



My next step would be:



Now, rationalize the denominator of the argument of the log function on the right.

Finished it, thanks. That was a big help :)

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