Cost and revenue function, calculate the intervals where the profit is increasing?

C(x) = 0.32x^2 - 0.00004x^3

R(x) = 0.848x^2 - 0.0002x^3

Im lost!!(Thinking)(Thinking)

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- Nov 18th 2012, 08:12 AMEmma22Calculate intervals - cost and revenue function
**Cost and revenue function, calculate the intervals where the profit is increasing?**

C(x) = 0.32x^2 - 0.00004x^3

R(x) = 0.848x^2 - 0.0002x^3

Im lost!!(Thinking)(Thinking) - Nov 18th 2012, 08:59 AMSpringFan25Re: Calculate intervals - cost and revenue function
the profit function is the difference between cost and revenue, so

$\displaystyle P(x) = (0.848 - 0.32)x^2 + (-0.0002--0.00004)x^3$

simplify terms in brackets...

$\displaystyle P(x) = 0.528x^2 -0.00016x^3$

now can you use the methods you have been taught to find the values of x where P(x) is increasing?