Convergent or divergent? Find sum if convergent. (problem 2)
Re: Convergent or divergent? Find sum if convergent. (problem 2)
Hello, superduper1!
This is a geometric series.
. . The first term is: . ^5}{\pi^1} \;=\;\text{-}\frac{32}{\pi})
. . The common ratio is: . 
The sum is: . 
. . } \;=\; \dfrac{\text{-}\frac{32}{\pi}}{\frac{\pi+2}{\pi}} \;=\; \frac{\text{-}32}{\pi+2})
Re: Convergent or divergent? Find sum if convergent. (problem 2)
How did you get the common ratio?
Re: Convergent or divergent? Find sum if convergent. (problem 2)
Quote:
Originally Posted by
superduper1 
How did you get the common ratio?
r is the ratio of the n+1th term by the nth term. In this case:
^{(n + 4) + 1}}{\pi ^ {n + 1}} }{\frac{(-2)^{n + 4}}{\pi ^ n} })
Re: Convergent or divergent? Find sum if convergent. (problem 2)
^{n+4}}{\pi^n})