Thread: Slope of a Curve

Let f(x) be the function . Then the quotient can be simplified to for: a= _____ & b= _____

Originally Posted by spyder12

Let f(x) be the function . Then the quotient can be simplified to for: a= _____ & b= _____

Can you do the algebra?

Now, putting these into the quotient gives you what?

ok so then that equals (1/h) / h right? then what do i do

Originally Posted by spyder12

ok so then that equals (1/h) / h right? then what do i do

you first need to combine the fractions in the numerator using the common denominator

No, how did you get that?

Originally Posted by MarkFL2

No, how did you get that?

methinks some creative algebra ...



... which, of course, is incorrect.

That was my inclination as well...many folks make this kind of error.

alright so then ( (1) / 16(h+16) ) / h = ( (1) / (16h+265) ) / h = (16h+256)^-1 / h , so to answer my question a= 16 & b=256

Yes, good work!

alright so then ( (1) / 16(h+16) ) / h = ( (1) / (16h+265) ) / h = (16h+256)^-1 / h , so to answer my question a= 16 & b=256

you may have "stumbled" onto the correct constants, but this is incorrect

Good catch, I only looked at the end result.