Find a formula of the form
where A,B,C are constants. Then apply this formula to find the antiderivative integral sin^3(x) dx
Hi chizimin10,
Your formula is missing, so I can't really help you with the main part of the problem. The antiderivative of $\displaystyle \sin{3x}$ is $\displaystyle -\frac{1}{3}\cos{3x}+C$, so when you apply the formula, you should get that answer.
- Hollywood