# Math Help - sin antiderivative

1. ## sin antiderivative

Find a formula of the form

where A,B,C are constants. Then apply this formula to find the antiderivative integral sin^3(x) dx

2. ## Re: sin antiderivative

Hi chizimin10,

Your formula is missing, so I can't really help you with the main part of the problem. The antiderivative of $\sin{3x}$ is $-\frac{1}{3}\cos{3x}+C$, so when you apply the formula, you should get that answer.

- Hollywood

3. ## Re: sin antiderivative

I am assuming it is something like:

$\sin^3(x)=\frac{A\sin(x)-\sin(Bx)}{C}$