# sin antiderivative

• November 13th 2012, 08:49 PM
chizmin10
sin antiderivative
Find a formula of the form
http://www3.wolframalpha.com/Calcula...=11&w=268&h=18
where A,B,C are constants. Then apply this formula to find the antiderivative integral sin^3(x) dx
• November 16th 2012, 07:36 AM
hollywood
Re: sin antiderivative
Hi chizimin10,

Your formula is missing, so I can't really help you with the main part of the problem. The antiderivative of $\sin{3x}$ is $-\frac{1}{3}\cos{3x}+C$, so when you apply the formula, you should get that answer.

- Hollywood
• November 16th 2012, 11:51 AM
MarkFL
Re: sin antiderivative
I am assuming it is something like:

$\sin^3(x)=\frac{A\sin(x)-\sin(Bx)}{C}$