Find a formula of the form

http://www3.wolframalpha.com/Calcula...=11&w=268&h=18

where A,B,C are constants. Then apply this formula to find the antiderivative integral sin^3(x) dx

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- Nov 13th 2012, 08:49 PMchizmin10sin antiderivative
Find a formula of the form

http://www3.wolframalpha.com/Calcula...=11&w=268&h=18

where A,B,C are constants. Then apply this formula to find the antiderivative integral sin^3(x) dx - Nov 16th 2012, 07:36 AMhollywoodRe: sin antiderivative
Hi chizimin10,

Your formula is missing, so I can't really help you with the main part of the problem. The antiderivative of $\displaystyle \sin{3x}$ is $\displaystyle -\frac{1}{3}\cos{3x}+C$, so when you apply the formula, you should get that answer.

- Hollywood - Nov 16th 2012, 11:51 AMMarkFLRe: sin antiderivative
I am assuming it is something like:

$\displaystyle \sin^3(x)=\frac{A\sin(x)-\sin(Bx)}{C}$